en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

area y=-x^2+4,y=3x^2

Solution

area

y = - x^{2} + 4, y = 3 x^{2}

Solution

\frac{16}{3}

+1

Decimal Notation

5.33333 \dots

Solution steps

Apply the area formula:

\int_{- 1}^{1} - 4 x^{2} + 4 d x

Solve

\int_{- 1}^{1} - 4 x^{2} + 4 d x : \frac{16}{3}

The area is:

= \frac{16}{3}

Popular Examples

derivative of log_{2}(2x+4)

\frac{d}{d x} (lo g_{2} (2 x + 4))

integral of x^7sqrt(ax^8-b)

\int x^{7} a x^{8} - b d x

derivative of (2x/(x^2+2))

\frac{d}{d x} (\frac{2 x}{x ^{2} + 2})

derivative of tan^2(sqrt(x))

\frac{d}{d x} (tan^{2} (x))

limit as x approaches 0 of e^{4x+2}

x \to 0 lim (e^{4 x + 2})

Frequently Asked Questions (FAQ)

What is area y=-x^2+4,y=3x^2 ?
The answer to area y=-x^2+4,y=3x^2 is 16/3