What is laplacetransform cos(5t) ?

The answer to laplacetransform cos(5t) is s/(s^2+25)

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laplacetransform cos(5t)

laplace transform

cos (5 t)

\frac{s}{s ^{2} + 25}

Solution steps

L {cos (5 t)}

Use Laplace Transform table:

L {cos (a t)} = \frac{s}{s ^{2} + a ^{2}}

L {cos (5 t)} = \frac{s}{s ^{2} + 5 ^{2}}

= \frac{s}{s ^{2} + 5 ^{2}}

= \frac{s}{s ^{2} + 25}

x \to 2 lim (\frac{x}{( - x + 2 ) ^{2}})

\frac{d y}{d x} = \frac{y ^{2} + 5 x x ^{2} + y ^{2}}{x y}

9 y^{^{''}} - 18 y^{^{'}} + 11 y = 0

x \to - 4 lim (\frac{2 x + 3}{x + 4})

\frac{d}{d x} ((a - x) a + x)

What is laplacetransform cos(5t) ?
The answer to laplacetransform cos(5t) is s/(s^2+25)