What is the solution for y^'=(2x^7e^{y/x}+x^5y^2)/(x^6y) ?

The solution for y^'=(2x^7e^{y/x}+x^5y^2)/(x^6y) is y=-\W((2ln(x)+c_{1})/e)x-x

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y^'=(2x^7e^{y/x}+x^5y^2)/(x^6y)

y^{^{'}} = \frac{2 x ^{7} e ^{\frac{y}{x}} + x ^{5} y ^{2}}{x ^{6} y}

y = - W (\frac{2 ln ( x ) + c _{1}}{e}) x - x

Solution steps

y^{'} (x) = \frac{2 x ^{7} e ^{\frac{y}{x}} + x ^{5} y ^{2}}{x ^{6} y}

Solve using substitution:

y = - W (\frac{2 ln ( x ) + c _{1}}{e}) x - x

y = - W (\frac{2 ln ( x ) + c _{1}}{e}) x - x

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\frac{d}{d x} ((2 x - y))

What is the solution for y^'=(2x^7e^{y/x}+x^5y^2)/(x^6y) ?
The solution for y^'=(2x^7e^{y/x}+x^5y^2)/(x^6y) is y=-\W((2ln(x)+c_{1})/e)x-x