What is the integral from 0 to 3 of sqrt(x^2-9) ?

The integral from 0 to 3 of sqrt(x^2-9) is -Does not exist

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integral from 0 to 3 of sqrt(x^2-9)

\int_{0}^{3} x^{2} - 9 d x

- Does not exist

Solution steps

\int_{0}^{3} x^{2} - 9 d x

Compute the indefinite integral:

\int x^{2} - 9 d x = 9 (\frac{1}{18} x x^{2} - 9 - \frac{1}{2} ln (\frac{x + x ^{2} - 9}{3})) + C

Compute the boundaries:

\int_{0}^{3} x^{2} - 9 d x = 0 -

Does not exist

= 0 - Does not exist

Simplify

= - Does not exist

\int 30 + \frac{60}{e ^{0.06 x}} d x

\frac{d}{d y} (6 x y)

\int \frac{1}{x a ^{2} - a ^{2} x ^{2}} d x

\frac{d y}{d x} = \frac{( y ^{3} )}{x ^{2}}

What is the integral from 0 to 3 of sqrt(x^2-9) ?
The integral from 0 to 3 of sqrt(x^2-9) is -Does not exist