What is the derivative of 2x^3-48x^2 ?

The derivative of 2x^3-48x^2 is 6x^2-96x

What is the first derivative of 2x^3-48x^2 ?

The first derivative of 2x^3-48x^2 is 6x^2-96x

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\frac{d}{d x} (2 x^{3} - 48 x^{2})

6 x^{2} - 96 x

Solution steps

\frac{d}{d x} (2 x^{3} - 48 x^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{3}) - \frac{d}{d x} (48 x^{2})

\frac{d}{d x} (2 x^{3}) = 6 x^{2}

\frac{d}{d x} (48 x^{2}) = 96 x

= 6 x^{2} - 96 x

\int 2 x - 1 d x

\int 16 θ sec^{2} (θ) d θ

y^{^{''}} - 6 y^{^{'}} + 9 y = 0, y (0) = 4, y^{^{'}} (0) = 0

\int_{- \frac{1}{3}}^{0} \frac{3}{4} (1 - x^{2}) d x

x + x^{2} + ln (x)

What is the derivative of 2x^3-48x^2 ?
The derivative of 2x^3-48x^2 is 6x^2-96x
What is the first derivative of 2x^3-48x^2 ?
The first derivative of 2x^3-48x^2 is 6x^2-96x