What is the derivative of f(x)=8x^3 ?

The derivative of f(x)=8x^3 is 24x^2

What is the first derivative of f(x)=8x^3 ?

The first derivative of f(x)=8x^3 is 24x^2

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derivative of

f (x) = 8 x^{3}

24 x^{2}

Solution steps

\frac{d}{d x} (8 x^{3})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 8 \frac{d}{d x} (x^{3})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 8 \cdot 3 x^{3 - 1}

Simplify

= 24 x^{2}

\frac{d}{d x} ((sec^{2} (x)) d x)

f (t) = t^{6} sin (t)

cos (- x)

\frac{\partial}{\partial y} (5 x + 4 y)

\int 2 x e^{3 x^{2}} d x

What is the derivative of f(x)=8x^3 ?
The derivative of f(x)=8x^3 is 24x^2
What is the first derivative of f(x)=8x^3 ?
The first derivative of f(x)=8x^3 is 24x^2