What is the derivative of be^{-x} ?

The derivative of be^{-x} is -be^{-x}

What is the first derivative of be^{-x} ?

The first derivative of be^{-x} is -be^{-x}

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\frac{d}{d x} (b e^{- x})

- b e^{- x}

Solution steps

\frac{d}{d x} (b e^{- x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= b \frac{d}{d x} (e^{- x})

Apply the chain rule:

e^{- x} \frac{d}{d x} (- x)

= e^{- x} \frac{d}{d x} (- x)

\frac{d}{d x} (- x) = - 1

= b e^{- x} (- 1)

Simplify

= - b e^{- x}

\int (x^{\frac{3}{2}} + 2 x + 1) d x

h \to 0 lim (\frac{\frac{2}{1 + h} - 2}{h})

- 7 x^{4} + 7 x^{3} - x^{2} + x

\int \frac{sec ( 3 x )}{cot ( 3 x )} d x

\frac{\partial}{\partial y} (\frac{y}{2 x + 3 y})

What is the derivative of be^{-x} ?
The derivative of be^{-x} is -be^{-x}
What is the first derivative of be^{-x} ?
The first derivative of be^{-x} is -be^{-x}