What is the derivative of cos(4e^{-8x}) ?

The derivative of cos(4e^{-8x}) is 32e^{-8x}sin(4e^{-8x})

What is the first derivative of cos(4e^{-8x}) ?

The first derivative of cos(4e^{-8x}) is 32e^{-8x}sin(4e^{-8x})

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\frac{d}{d x} (cos (4 e^{- 8 x}))

32 e^{- 8 x} sin (4 e^{- 8 x})

Solution steps

\frac{d}{d x} (cos (4 e^{- 8 x}))

Apply the chain rule:

- sin (4 e^{- 8 x}) \frac{d}{d x} (4 e^{- 8 x})

= - sin (4 e^{- 8 x}) \frac{d}{d x} (4 e^{- 8 x})

\frac{d}{d x} (4 e^{- 8 x}) = - 32 e^{- 8 x}

= - sin (4 e^{- 8 x}) (- 32 e^{- 8 x})

Simplify

= 32 e^{- 8 x} sin (4 e^{- 8 x})

f (x) = x + \frac{2}{x}, (2, 3)

\frac{1}{( 1 + x ^{2} ) ^{2}}

\frac{x + 1}{x + 7}

(2 x y^{2} + 2 y) + (2 x^{2} y + 2 x) y^{^{'}} = 0

e^{3 x} cos (6 x)

What is the derivative of cos(4e^{-8x}) ?
The derivative of cos(4e^{-8x}) is 32e^{-8x}sin(4e^{-8x})
What is the first derivative of cos(4e^{-8x}) ?
The first derivative of cos(4e^{-8x}) is 32e^{-8x}sin(4e^{-8x})