What is the derivative of 2(6x^2-7x(12x-7)) ?

The derivative of 2(6x^2-7x(12x-7)) is 2(216x^2-252x+49)

What is the first derivative of 2(6x^2-7x(12x-7)) ?

The first derivative of 2(6x^2-7x(12x-7)) is 2(216x^2-252x+49)

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\frac{d}{d x} (2 (6 x^{2} - 7 x) (12 x - 7))

2 (216 x^{2} - 252 x + 49)

Solution steps

\frac{d}{d x} (2 (6 x^{2} - 7 x) (12 x - 7))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} ((6 x^{2} - 7 x) (12 x - 7))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = 6 x^{2} - 7 x, g = 12 x - 7

= 2 (\frac{d}{d x} (6 x^{2} - 7 x) (12 x - 7) + \frac{d}{d x} (12 x - 7) (6 x^{2} - 7 x))

\frac{d}{d x} (6 x^{2} - 7 x) = 12 x - 7

\frac{d}{d x} (12 x - 7) = 12

= 2 ((12 x - 7) (12 x - 7) + 12 (6 x^{2} - 7 x))

Simplify

2 ((12 x - 7) (12 x - 7) + 12 (6 x^{2} - 7 x)) : 2 (216 x^{2} - 252 x + 49)

= 2 (216 x^{2} - 252 x + 49)

\int e^{- s x} (2 - x) d x

x \to 1 lim (\frac{1}{x ^{3} - 1})

\frac{d}{d x} (3 - 3 cos (x))

\frac{d y}{d x} = (x - 4) e^{- 2 y}

y^{^{'}} = 6 x^{2} \cdot y

What is the derivative of 2(6x^2-7x(12x-7)) ?
The derivative of 2(6x^2-7x(12x-7)) is 2(216x^2-252x+49)
What is the first derivative of 2(6x^2-7x(12x-7)) ?
The first derivative of 2(6x^2-7x(12x-7)) is 2(216x^2-252x+49)