What is the solution for (dy)/(dx)=e^{3y+10x} ?

The solution for (dy)/(dx)=e^{3y+10x} is y=-(ln(-3/10 e^{10x}-c_{1}))/3

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(dy)/(dx)=e^{3y+10x}

\frac{d y}{d x} = e^{3 y + 10 x}

y = - \frac{ln ( - \frac{3}{10} e ^{10 x} - c _{1} )}{3}

Solution steps

\frac{d y}{d x} = e^{3 y + 10 x}

Solve separable ODE:

y = - \frac{ln ( - \frac{3}{10} e ^{10 x} - c _{1} )}{3}

y = - \frac{ln ( - \frac{3}{10} e ^{10 x} - c _{1} )}{3}

\frac{d}{d x} (sin (x) (1 - cos (x)))

n = 0 \sum \infty \frac{1}{2 - e ^{- n}}

f (x) = - 10 x sin (5 x^{2} + 5)

\frac{d}{d x} ((4 - x^{\frac{2}{3}})^{\frac{2}{3}})

\frac{d}{d x} (\frac{1}{10 x ^{\frac{9}{10}}})

What is the solution for (dy)/(dx)=e^{3y+10x} ?
The solution for (dy)/(dx)=e^{3y+10x} is y=-(ln(-3/10 e^{10x}-c_{1}))/3