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Popular >

y^'-2y=x

Solution

y^{^{'}} - 2 y = x

Solution

y = - \frac{2 x + 1}{4} + c_{1} e^{2 x}

Solution steps

y^{'} (x) - 2 y = x

Solve linear ODE:

y = - \frac{2 x + 1}{4} + c_{1} e^{2 x}

y = - \frac{2 x + 1}{4} + c_{1} e^{2 x}

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Frequently Asked Questions (FAQ)

What is the solution for y^'-2y=x ?
The solution for y^'-2y=x is y=-(2x+1)/4+c_{1}e^{2x}