What is the solution for xy^{''}+2y^'=16x^2 ?

The solution for xy^{''}+2y^'=16x^2 is y=c_{1}+(c_{2})/x+(4x^3)/3

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xy^{''}+2y^'=16x^2

x y^{^{''}} + 2 y^{^{'}} = 16 x^{2}

y = c_{1} + \frac{c _{2}}{x} + \frac{4 x ^{3}}{3}

Solution steps

x y^{''} (x) + 2 y^{'} (x) = 16 x^{2}

Solve linear ODE:

y = c_{1} + \frac{c _{2}}{x} + \frac{4 x ^{3}}{3}

y = c_{1} + \frac{c _{2}}{x} + \frac{4 x ^{3}}{3}

\int_{0}^{N} e^{(- s t)} e^{- 5 t} d t

2000 + 530 (ln (x))

\int_{1}^{16} t ln (t) d t

x tan (x)

θ \to 0 lim (\frac{1 - cos ( θ )}{θ})

What is the solution for xy^{''}+2y^'=16x^2 ?
The solution for xy^{''}+2y^'=16x^2 is y=c_{1}+(c_{2})/x+(4x^3)/3