What is the solution for (x^2-y^2)dx+xydy=0 ?

The solution for (x^2-y^2)dx+xydy=0 is y=xsqrt(-2ln(x)+c_{1)},y=-xsqrt(-2ln(x)+c_{1)}

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(x^2-y^2)dx+xydy=0

(x^{2} - y^{2}) d x + x y d y = 0

y = x - 2 ln (x) + c_{1}, y = - x - 2 ln (x) + c_{1}

Solution steps

(x^{2} - y^{2}) d x + x y d y = 0

Solve Bernoulli ODE:

y = x - 2 ln (x) + c_{1}, y = - x - 2 ln (x) + c_{1}

y = x - 2 ln (x) + c_{1}, y = - x - 2 ln (x) + c_{1}

\int_{7}^{13} \frac{y}{y ^{2} - 3 y - 4} d y

f^{^{'''}} (x) = 6 (x^{- 2})

\frac{s + 10}{s ^{2} - s - 2}

\int_{2}^{4} (\frac{2}{x} + 3 x)^{2} d x

\int e^{x} - e^{2 x} d x

What is the solution for (x^2-y^2)dx+xydy=0 ?
The solution for (x^2-y^2)dx+xydy=0 is y=xsqrt(-2ln(x)+c_{1)},y=-xsqrt(-2ln(x)+c_{1)}