What is the tangent of 6cos(x) ?

The tangent of 6cos(x) is y=-6sin(a_{0})x+6cos(a_{0})+6a_{0}sin(a_{0})

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tangent of 6cos(x)

tangent of

6 cos (x)

y = - 6 sin (a_{0}) x + 6 cos (a_{0}) + 6 a_{0} sin (a_{0})

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, 6 cos (a_{0}))

Find the slope of

y = 6 cos (x) : \frac{d y}{d x} = - 6 sin (x)

Compute the slope of

y = 6 cos (x)

x = a_{0} : m = - 6 sin (a_{0})

Find the line with slope m=

- 6 sin (a_{0})

and passing through

(a_{0}, 6 cos (a_{0})) : y = - 6 sin (a_{0}) x + 6 cos (a_{0}) + 6 a_{0} sin (a_{0})

y = - 6 sin (a_{0}) x + 6 cos (a_{0}) + 6 a_{0} sin (a_{0})

y^{^{''}} + 16 y = - 32 sec (4 t)

\int 3 y^{2} - 2 x d y

\frac{d}{d x} (ln (ln (2 x^{4})))

\int \frac{4 x}{x ^{4} - 12 x ^{2} + 45} d x

f (x) = 4 x^{2}, at x = 1

What is the tangent of 6cos(x) ?
The tangent of 6cos(x) is y=-6sin(a_{0})x+6cos(a_{0})+6a_{0}sin(a_{0})