What is the slope of y= 1/(x-2) ?

The slope of y= 1/(x-2) is -1/((x-2)^2)

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slope of y= 1/(x-2)

slope

y = \frac{1}{x - 2}

- \frac{1}{( x - 2 ) ^{2}}

Solution steps

y = \frac{1}{x - 2}

In order to find the slope of the function, take the derivative of

\frac{1}{x - 2}

\frac{d}{d x} (\frac{1}{x - 2}) = - \frac{1}{( x - 2 ) ^{2}}

- \frac{1}{( x - 2 ) ^{2}}

\int 2 cos (θ) + 2 d θ

\int \frac{1}{49 e ^{- 8 x} + e ^{8 x}} d x

\frac{d}{d x} (2 sin^{2} (π x))

\frac{\partial}{\partial x} (ln (x - 3 y))

\frac{d}{d x} (1 + cos (3 π x))