What is the integral from 0 to 6 of e^x ?

The integral from 0 to 6 of e^x is e^6-1

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integral from 0 to 6 of e^x

\int_{0}^{6} e^{x} d x

e^{6} - 1

Decimal Notation

402.42879 \dots

Solution steps

\int_{0}^{6} e^{x} d x

Use the common integral:

\int e^{x} d x = e^{x}

= [e^{x}]_{0}^{6}

Compute the boundaries:

e^{6} - 1

= e^{6} - 1

(\frac{y}{x} + 9 x) d x + (ln (x) - 2) d y = 0

\int (x^{n} ln (x)) d x

\int_{- 2}^{0} 3 w 4 - w^{2} d w

t \to 0 lim (\frac{e ^{t} - 1}{t})

f (x) = (\frac{x}{7} + \frac{7}{x})^{7}

What is the integral from 0 to 6 of e^x ?
The integral from 0 to 6 of e^x is e^6-1