What is the integral from 1 to 5 of 6/(x^2) ?

The integral from 1 to 5 of 6/(x^2) is 24/5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 1 to 5 of 6/(x^2)

\int_{1}^{5} \frac{6}{x ^{2}} d x

\frac{24}{5}

Decimal Notation

4.8

Solution steps

\int_{1}^{5} \frac{6}{x ^{2}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 6 \cdot \int_{1}^{5} \frac{1}{x ^{2}} d x

Apply the Power Rule

: [- \frac{1}{x}]_{1}^{5}

= 6 [- \frac{1}{x}]_{1}^{5}

Compute the boundaries:

\frac{4}{5}

= 6 \cdot \frac{4}{5}

Simplify

= \frac{24}{5}

\frac{\partial}{\partial x} (5 2 x)

\int \frac{7 ln ( x )}{x ^{4}} d x

n = 1 \sum \infty n^{2} e^{- n^{2}}

\int \frac{3 x ^{2}}{1 - x ^{2}} d x

\int \frac{1}{p - z} + \frac{1}{z} d z

What is the integral from 1 to 5 of 6/(x^2) ?
The integral from 1 to 5 of 6/(x^2) is 24/5