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Popular >

integral of 4(x-1)

Solution

\int 4 (x - 1) d x

Solution

4 (\frac{x ^{2}}{2} - x) + C

Solution steps

\int 4 (x - 1) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 4 \cdot \int x - 1 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= 4 (\int x d x - \int 1 d x)

\int x d x = \frac{x ^{2}}{2}

\int 1 d x = x

= 4 (\frac{x ^{2}}{2} - x)

Add a constant to the solution

= 4 (\frac{x ^{2}}{2} - x) + C

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f (x) = \frac{5}{4} x^{\frac{4}{3}}

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x \to 6 - lim (\frac{- 6}{x + 6})

partialfraction (x^3)/(x-2)partial fractions

\frac{x ^{3}}{x - 2}

(dy)/(dx)=y^2+a^2

\frac{d y}{d x} = y^{2} + a^{2}

Frequently Asked Questions (FAQ)

What is the integral of 4(x-1) ?
The integral of 4(x-1) is 4((x^2)/2-x)+C