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Popular >

x^{''}=-k^2x

Solution

x^{^{''}} = - k^{2} x

Solution

x = c_{1} cos (k t) + c_{2} sin (k t)

Solution steps

x^{''} (t) = - k^{2} x

Solve linear ODE:

x = c_{1} cos (k t) + c_{2} sin (k t)

x = c_{1} cos (k t) + c_{2} sin (k t)

Popular Examples

(2 + x) y^{^{'}} - x y = 0

laplacetransform e^s laplace transform

e^{s}

limit as x approaches c of 5

x \to c lim (5)

tangent of f(x)=x^4-5x^2+4,\at x=2 tangent of

f (x) = x^{4} - 5 x^{2} + 4, at x = 2

(dy)/(dx)-y/x =xe^x

\frac{d y}{d x} - \frac{y}{x} = x e^{x}

Frequently Asked Questions (FAQ)

What is the solution for x^{''}=-k^2x ?
The solution for x^{''}=-k^2x is x=c_{1}cos(kt)+c_{2}sin(kt)