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Popular >

derivative of f(x)=(x^5)/5-(4x^3)/3+4x

Solution

derivative of

f (x) = \frac{x ^{5}}{5} - \frac{4 x ^{3}}{3} + 4 x

Solution

x^{4} - 4 x^{2} + 4

Solution steps

\frac{d}{d x} (\frac{x ^{5}}{5} - \frac{4 x ^{3}}{3} + 4 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{x ^{5}}{5}) - \frac{d}{d x} (\frac{4 x ^{3}}{3}) + \frac{d}{d x} (4 x)

\frac{d}{d x} (\frac{x ^{5}}{5}) = x^{4}

\frac{d}{d x} (\frac{4 x ^{3}}{3}) = 4 x^{2}

\frac{d}{d x} (4 x) = 4

= x^{4} - 4 x^{2} + 4

Popular Examples

tangent of f(x)=7e^{-0.03x},\at x=9 tangent of

f (x) = 7 e^{- 0.03 x}, at x = 9

derivative of y=((3x-9))/((2x+8))derivative of

y = \frac{( 3 x - 9 )}{( 2 x + 8 )}

integral of (x^3+x)e^{-4x}

\int (x^{3} + x) e^{- 4 x} d x

integral of (2x)/(sqrt(x^2-1))

\int \frac{2 x}{x ^{2} - 1} d x

derivative of 2(3-x^2^5)

\frac{d}{d x} (2 (3 - x^{2})^{5})

Frequently Asked Questions (FAQ)

What is the derivative of f(x)=(x^5)/5-(4x^3)/3+4x ?
The derivative of f(x)=(x^5)/5-(4x^3)/3+4x is x^4-4x^2+4
What is the first derivative of f(x)=(x^5)/5-(4x^3)/3+4x ?
The first derivative of f(x)=(x^5)/5-(4x^3)/3+4x is x^4-4x^2+4