What is (\partial)/(\partial y)(zln(y)+e^2) ?

The answer to (\partial)/(\partial y)(zln(y)+e^2) is z/y

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial y)(zln(y)+e^2)

\frac{\partial}{\partial y} (z ln (y) + e^{2})

\frac{z}{y}

Solution steps

\frac{\partial}{\partial y} (z ln (y) + e^{2})

Treat

z

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (z ln (y)) + \frac{\partial}{\partial y} (e^{2})

\frac{\partial}{\partial y} (z ln (y)) = \frac{z}{y}

\frac{\partial}{\partial y} (e^{2}) = 0

= \frac{z}{y} + 0

Simplify

= \frac{z}{y}

\frac{d}{d x} (- x e^{\frac{y}{x}})

\int_{0}^{\frac{π}{2}} cot (x) d x

x \to 0 lim ((1 + 8 x)^{\frac{6}{x}})

\frac{4 - 3 x - x ^{2}}{x ^{2} - 1}

\frac{d x}{d y} = 3 x

What is (\partial)/(\partial y)(zln(y)+e^2) ?
The answer to (\partial)/(\partial y)(zln(y)+e^2) is z/y