What is the tangent of f(x)=sin(sin(x)),(3pi,0) ?

The tangent of f(x)=sin(sin(x)),(3pi,0) is y=-x+3pi

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of f(x)=sin(sin(x)),(3pi,0)

tangent of

f (x) = sin (sin (x)), (3 π, 0)

y = - x + 3 π

Solution steps

Find the slope of

f (x) = sin (sin (x)) : \frac{df ( x )}{d x} = cos (sin (x)) cos (x)

Compute the slope of

f (x) = sin (sin (x))

(3 π, 0) : m = - 1

Find the line with slope m=

- 1

and passing through

(3 π, 0) : y = - x + 3 π

y = - x + 3 π

f (x) = 1000 - x - \frac{1}{8} x^{2}

f (x) = x - 3

y^{^{''}} + 4 y^{^{'}} + 8 y = 325 e^{2 t} cos (5 t)

\int 2 y x d x

\frac{d}{d x} (\frac{x + 1}{x ^{2} - 3})

What is the tangent of f(x)=sin(sin(x)),(3pi,0) ?
The tangent of f(x)=sin(sin(x)),(3pi,0) is y=-x+3pi