What is the solution for x^2y^{''}-5xy^'+9y=0,y(1)=-5,y^'(1)=-17 ?

The solution for x^2y^{''}-5xy^'+9y=0,y(1)=-5,y^'(1)=-17 is y=-5x^3-2x^3ln(x)

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x^2y^{''}-5xy^'+9y=0,y(1)=-5,y^'(1)=-17

x^{2} y^{^{''}} - 5 x y^{^{'}} + 9 y = 0, y (1) = - 5, y^{^{'}} (1) = - 17

y = - 5 x^{3} - 2 x^{3} ln (x)

Solution steps

x^{2} y^{''} (x) - 5 x y^{'} (x) + 9 y = 0

Solve linear ODE:

y = - 5 x^{3} - 2 x^{3} ln (x)

y = - 5 x^{3} - 2 x^{3} ln (x)

(- 3.1) (0.3)

4 arcsin (x)

x \to 0 lim (2 x^{3} + ln (x))

\frac{d}{d x} (\frac{3 3 x ^{2}}{2})

\frac{d}{d x} (x ln (9 x))

What is the solution for x^2y^{''}-5xy^'+9y=0,y(1)=-5,y^'(1)=-17 ?
The solution for x^2y^{''}-5xy^'+9y=0,y(1)=-5,y^'(1)=-17 is y=-5x^3-2x^3ln(x)