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Popular >

y^'=sin(x)

Solution

y^{^{'}} = sin (x)

Solution

y = - cos (x) + c_{1}

Solution steps

y^{'} (x) = sin (x)

If

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

y = \int sin (x) d x

\int sin (x) d x = - cos (x) + c_{1}

y = - cos (x) + c_{1}

Popular Examples

limit as x approaches 1 of 2x^2

x \to 1 lim (2 x^{2})

area f(x)=((2-x^2))/2 ,[-5/4 , 5/4 ]area

f (x) = \frac{( 2 - x ^{2} )}{2}, [- \frac{5}{4}, \frac{5}{4}]

sum from k=1 to infinity of k^3e^{-k^2}

k = 1 \sum \infty k^{3} e^{- k^{2}}

(x^2+y)dx+(x-e^y)dy=0

(x^{2} + y) d x + (x - e^{y}) d y = 0

derivative of y=4 derivative of

y = 4

Frequently Asked Questions (FAQ)

What is the solution for y^'=sin(x) ?
The solution for y^'=sin(x) is y=-cos(x)+c_{1}