What is the solution for y^'+y/(6.96)=0.0025862069 ?

The solution for y^'+y/(6.96)=0.0025862069 is y=-e^{(-25t-c_{1})/(174)}+0.01800…

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y^'+y/(6.96)=0.0025862069

y^{^{'}} + \frac{y}{6.96} = 0.0025862069

y = - e^{\frac{- 25 t - c _{1}}{174}} + 0.01800 \dots

Solution steps

y^{'} (t) + \frac{y}{6.96} = 0.0025862069

Solve separable ODE:

y = - e^{\frac{- 25 t - c _{1}}{174}} + 0.01800 \dots

y = - e^{\frac{- 25 t - c _{1}}{174}} + 0.01800 \dots

\frac{d}{d x} (ln (x^{\frac{1}{5}}))

\int x^{2} + x^{- 2} d x

sin (2 x) d x + cos (6 y) d y = 0

y = 4 x^{2}, y = 6 x^{2}, 5 x + y = 6

What is the solution for y^'+y/(6.96)=0.0025862069 ?
The solution for y^'+y/(6.96)=0.0025862069 is y=-e^{(-25t-c_{1})/(174)}+0.01800…