What is the solution for (dy)/(dx)+6tan(6x)y=-8cos(6x) ?

The solution for (dy)/(dx)+6tan(6x)y=-8cos(6x) is y=-(8x)/(sec(6x))+(c_{1})/(sec(6x))

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(dy)/(dx)+6tan(6x)y=-8cos(6x)

\frac{d y}{d x} + 6 tan (6 x) y = - 8 cos (6 x)

y = - \frac{8 x}{sec ( 6 x )} + \frac{c _{1}}{sec ( 6 x )}

Solution steps

\frac{d y}{d x} + 6 tan (6 x) y = - 8 cos (6 x)

Solve linear ODE:

y = - \frac{8 x}{sec ( 6 x )} + \frac{c _{1}}{sec ( 6 x )}

y = - \frac{8 x}{sec ( 6 x )} + \frac{c _{1}}{sec ( 6 x )}

\int \frac{x - 1}{x ^{2} + 2 x} d x

(1 - x^{2})

\int 8 \frac{tan ^{3} ( 2 x )}{x} d x

n = 2 \sum \infty n (n - 1) x^{n}

- x + 5, 0, 2

What is the solution for (dy)/(dx)+6tan(6x)y=-8cos(6x) ?
The solution for (dy)/(dx)+6tan(6x)y=-8cos(6x) is y=-(8x)/(sec(6x))+(c_{1})/(sec(6x))