What is the derivative of (2-x-3x^3)(7+x^5) ?

The derivative of (2-x-3x^3)(7+x^5) is -24x^7-6x^5+10x^4-63x^2-7

What is the first derivative of (2-x-3x^3)(7+x^5) ?

The first derivative of (2-x-3x^3)(7+x^5) is -24x^7-6x^5+10x^4-63x^2-7

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derivative of

(2 - x - 3 x^{3}) (7 + x^{5})

- 24 x^{7} - 6 x^{5} + 10 x^{4} - 63 x^{2} - 7

Solution steps

\frac{d}{d x} ((2 - x - 3 x^{3}) (7 + x^{5}))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = 2 - x - 3 x^{3}, g = 7 + x^{5}

= \frac{d}{d x} (2 - x - 3 x^{3}) (7 + x^{5}) + \frac{d}{d x} (7 + x^{5}) (2 - x - 3 x^{3})

\frac{d}{d x} (2 - x - 3 x^{3}) = - 9 x^{2} - 1

\frac{d}{d x} (7 + x^{5}) = 5 x^{4}

= (- 9 x^{2} - 1) (7 + x^{5}) + 5 x^{4} (2 - x - 3 x^{3})

Simplify

(- 9 x^{2} - 1) (7 + x^{5}) + 5 x^{4} (2 - x - 3 x^{3}) : - 24 x^{7} - 6 x^{5} + 10 x^{4} - 63 x^{2} - 7

= - 24 x^{7} - 6 x^{5} + 10 x^{4} - 63 x^{2} - 7

(s^{\frac{- 1}{2}} + 7 s) (1 - s^{- 1})

\frac{d}{d x} ((2 - x^{3})^{3})

x \to - 3 lim (19 + x)

x^{2} e^{x} - 2 x e^{x} + 2 e^{x}

8 x^{4}

What is the derivative of (2-x-3x^3)(7+x^5) ?
The derivative of (2-x-3x^3)(7+x^5) is -24x^7-6x^5+10x^4-63x^2-7
What is the first derivative of (2-x-3x^3)(7+x^5) ?
The first derivative of (2-x-3x^3)(7+x^5) is -24x^7-6x^5+10x^4-63x^2-7