What is the sum from n=5 to infinity of 1/(n^2) ?

The sum from n=5 to infinity of 1/(n^2) is converges

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sum from n=5 to infinity of 1/(n^2)

n = 5 \sum \infty \frac{1}{n ^{2}}

converges

Solution steps

n = 5 \sum \infty \frac{1}{n ^{2}}

Apply p-Series Test:

converges

= converges

\int (\frac{1}{y} sin (\frac{x}{y}) + x) d x

\frac{d}{d x} (arctan (e^{x} + 1))

\int_{- 1}^{2} (x^{2} - x - 2) d x

x \to - 5 lim (\frac{x ^{2}}{5 - x})

\frac{d}{d x} (\frac{9}{x ^{4}})

What is the sum from n=5 to infinity of 1/(n^2) ?
The sum from n=5 to infinity of 1/(n^2) is converges