What is the solution for y^{''}+22y=0 ?

The solution for y^{''}+22y=0 is y=c_{1}cos(sqrt(22)t)+c_{2}sin(sqrt(22)t)

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y^{''}+22y=0

y^{^{''}} + 22 y = 0

y = c_{1} cos (22 t) + c_{2} sin (22 t)

Solution steps

y^{''} (t) + 22 y = 0

Solve linear ODE:

y = c_{1} cos (22 t) + c_{2} sin (22 t)

y = c_{1} cos (22 t) + c_{2} sin (22 t)

\frac{\partial}{\partial y} (x^{2} + x y + y^{2})

10 - 7 x, y = 0, x^{2} - 20

\int 2 x + 3 x^{- 2} d x

\int \frac{5 sin ^{3} ( x )}{x} d x

\frac{d y}{d t} + 2 y = 3 e^{t}, y (0) = 1

What is the solution for y^{''}+22y=0 ?
The solution for y^{''}+22y=0 is y=c_{1}cos(sqrt(22)t)+c_{2}sin(sqrt(22)t)