What is the derivative of 1/(-2x^2) ?

The derivative of 1/(-2x^2) is 1/(x^3)

What is the first derivative of 1/(-2x^2) ?

The first derivative of 1/(-2x^2) is 1/(x^3)

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\frac{d}{d x} (\frac{1}{- 2 x ^{2}})

\frac{1}{x ^{3}}

Solution steps

\frac{d}{d x} (\frac{1}{- 2 x ^{2}})

Simplify

\frac{1}{- 2 x ^{2}} : - \frac{1}{2 x ^{2}}

= \frac{d}{d x} (- \frac{1}{2 x ^{2}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - \frac{1}{2} \frac{d}{d x} (\frac{1}{x ^{2}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= - \frac{1}{2} \frac{d}{d x} (x^{- 2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= - \frac{1}{2} (- 2 x^{- 2 - 1})

Simplify

- \frac{1}{2} (- 2 x^{- 2 - 1}) : \frac{1}{x ^{3}}

= \frac{1}{x ^{3}}

n = 0 \sum \infty (2 x)^{n}

f (x) = x 2^{x}

(- 2.3) (2.2)

x \to 0 - lim (x \cdot arctan (\frac{1}{x}))

\frac{d y}{d x} = \frac{2 x}{1 + 2 y}, y (2) = 0

What is the derivative of 1/(-2x^2) ?
The derivative of 1/(-2x^2) is 1/(x^3)
What is the first derivative of 1/(-2x^2) ?
The first derivative of 1/(-2x^2) is 1/(x^3)