What is the derivative of 3sqrt(4-1/2 x) ?

The derivative of 3sqrt(4-1/2 x) is -3/(2sqrt(2)\sqrt{8-x)}

What is the first derivative of 3sqrt(4-1/2 x) ?

The first derivative of 3sqrt(4-1/2 x) is -3/(2sqrt(2)\sqrt{8-x)}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} (3 4 - \frac{1}{2} x)

- \frac{3}{2 2 8 - x}

Solution steps

\frac{d}{d x} (3 4 - \frac{1}{2} x)

Simplify

3 4 - \frac{1}{2} x : 3 \frac{8 - x}{2}

= \frac{d}{d x} (3 \frac{8 - x}{2})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 \frac{d}{d x} (\frac{8 - x}{2})

Apply the chain rule:

\frac{1}{2 \frac{8 - x}{2}} \frac{d}{d x} (\frac{8 - x}{2})

= \frac{1}{2 \frac{8 - x}{2}} \frac{d}{d x} (\frac{8 - x}{2})

\frac{d}{d x} (\frac{8 - x}{2}) = - \frac{1}{2}

= 3 \cdot \frac{1}{2 \frac{8 - x}{2}} (- \frac{1}{2})

Simplify

3 \cdot \frac{1}{2 \frac{8 - x}{2}} (- \frac{1}{2}) : - \frac{3}{2 2 8 - x}

= - \frac{3}{2 2 8 - x}

\int x \cdot sin (4 x) d x

\frac{d}{d x} (\frac{- 2 x}{x ^{2} + 1})

\int 12 e^{3 x - 1} d x

\int \frac{6}{( 1 - 2 x ) ^{3}} d x

x \frac{d y}{d x} + y = - 6 x y^{2}

What is the derivative of 3sqrt(4-1/2 x) ?
The derivative of 3sqrt(4-1/2 x) is -3/(2sqrt(2)\sqrt{8-x)}
What is the first derivative of 3sqrt(4-1/2 x) ?
The first derivative of 3sqrt(4-1/2 x) is -3/(2sqrt(2)\sqrt{8-x)}