What is the tangent of f(x)=sqrt(5-3x),\at x=-2 ?

The tangent of f(x)=sqrt(5-3x),\at x=-2 is y=-3/(2sqrt(11))x+sqrt(11)-3/(sqrt(11))

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tangent of f(x)=sqrt(5-3x),\at x=-2

tangent of

f (x) = 5 - 3 x, at x = - 2

y = - \frac{3}{2 11} x + 11 - \frac{3}{11}

Solution steps

Find the tangent point:

(- 2, 11)

Find the slope of

f (x) = 5 - 3 x : \frac{df ( x )}{d x} = - \frac{3}{2 5 - 3 x}

Compute the slope of

f (x) = 5 - 3 x

x = - 2 : m = - \frac{3}{2 11}

Find the line with slope m=

- \frac{3}{2 11}

and passing through

(- 2, 11) : y = - \frac{3}{2 11} x + 11 - \frac{3}{11}

y = - \frac{3}{2 11} x + 11 - \frac{3}{11}

x \to - 5 lim (4 x^{3} + x)

\frac{d y}{d x} + 3 y = 2

x \to 3 lim (- 8)

\int \frac{1}{( 3 + x ) ^{2}} d x

\frac{d}{d t} (ln (\frac{a + b t}{a - b t}))

What is the tangent of f(x)=sqrt(5-3x),\at x=-2 ?
The tangent of f(x)=sqrt(5-3x),\at x=-2 is y=-3/(2sqrt(11))x+sqrt(11)-3/(sqrt(11))