What is the integral from 1 to 2 of x^2 ?

The integral from 1 to 2 of x^2 is 7/3

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integral from 1 to 2 of x^2

\int_{1}^{2} x^{2} d x

\frac{7}{3}

Decimal Notation

2.33333 \dots

Solution steps

\int_{1}^{2} x^{2} d x

Apply the Power Rule

: [\frac{x ^{3}}{3}]_{1}^{2}

= [\frac{x ^{3}}{3}]_{1}^{2}

Compute the boundaries:

\frac{7}{3}

= \frac{7}{3}

\int_{0}^{2} \frac{x}{16 - x ^{2}} d x

\int \frac{5}{2 x + 7} d x

x \to 2 lim (\frac{x + 4}{3 x - 1})

\int \frac{1}{( 4 x ^{2} - 1 ) ^{2}} d x

\int 2 x (x^{2} + 8)^{7} d x

What is the integral from 1 to 2 of x^2 ?
The integral from 1 to 2 of x^2 is 7/3