What is the tangent of 2/(x^2),\at (1.2) ?

The tangent of 2/(x^2),\at (1.2) is y=-4/(a_{0)^3}x+6/(a_{0)^2}

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tangent of 2/(x^2),\at (1.2)

tangent of

\frac{2}{x ^{2}}, at (1.2)

y = - \frac{4}{a _{0}^{3}} x + \frac{6}{a _{0}^{2}}

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, \frac{2}{a _{0}^{2}})

Find the slope of

y = \frac{2}{x ^{2}} : \frac{d y}{d x} = - \frac{4}{x ^{3}}

Compute the slope of

y = \frac{2}{x ^{2}}

x = a_{0} : m = - \frac{4}{a _{0}^{3}}

Find the line with slope m=

- \frac{4}{a _{0}^{3}}

and passing through

(a_{0}, \frac{2}{a _{0}^{2}}) : y = - \frac{4}{a _{0}^{3}} x + \frac{6}{a _{0}^{2}}

y = - \frac{4}{a _{0}^{3}} x + \frac{6}{a _{0}^{2}}

\int \frac{1}{x ln ^{4} ( x )} d x

y^{^{'}} = y^{\frac{1}{3}}

\frac{d y}{d x} = 5 x + 15 y

f (x) = \frac{x}{4 x + 3 ln ( x )}

y = \frac{- 4 x ^{2} + 12}{2 x + 2}

What is the tangent of 2/(x^2),\at (1.2) ?
The tangent of 2/(x^2),\at (1.2) is y=-4/(a_{0)^3}x+6/(a_{0)^2}