What is the integral of cot^4(x) ?

The integral of cot^4(x) is -1/3 cot^3(x)+x+cot(x)+C

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integral of cot^4(x)

\int cot^{4} (x) d x

- \frac{1}{3} cot^{3} (x) + x + cot (x) + C

Solution steps

\int cot^{4} (x) d x

Apply Integral Reduction

= - \frac{cot ^{3} ( x )}{3} - \int cot^{2} (x) d x

\int cot^{2} (x) d x = - x - cot (x)

= - \frac{cot ^{3} ( x )}{3} - (- x - cot (x))

Simplify

- \frac{cot ^{3} ( x )}{3} - (- x - cot (x)) : - \frac{1}{3} cot^{3} (x) + x + cot (x)

= - \frac{1}{3} cot^{3} (x) + x + cot (x)

Add a constant to the solution

= - \frac{1}{3} cot^{3} (x) + x + cot (x) + C

\frac{d y}{d x} = \frac{y}{x}

\int \frac{1}{( π x - 1 )} d x

\int 4^{l n (x)} d x

\frac{d ^{2} y}{d x ^{2}} + 5 \frac{d y}{d x} + 6 y = 0

(1, 7), (10, 1)

What is the integral of cot^4(x) ?
The integral of cot^4(x) is -1/3 cot^3(x)+x+cot(x)+C