What is the integral from-infinity to 0 of 1/(6-10x) ?

The integral from-infinity to 0 of 1/(6-10x) is diverges

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integral from-infinity to 0 of 1/(6-10x)

\int_{- \infty}^{0} \frac{1}{6 - 10 x} d x

diverges

Solution steps

\int_{- \infty}^{0} \frac{1}{6 - 10 x} d x

Compute the indefinite integral:

\int \frac{1}{6 - 10 x} d x = - \frac{1}{10} ln ∣ 6 - 10 x ∣ + C

Compute the boundaries:

\int_{- \infty}^{0} \frac{1}{6 - 10 x} d x =

diverges

= diverges

∣ 9 x ∣, x^{2} - 10

\int q^{2} cos (7 q) d q

\frac{d y}{d x} = \frac{( y - y ^{3} )}{a ^{2}}, y (0) = b

\frac{\partial}{\partial x} (b x e^{5 x y})

x \to (- 1) + lim (\frac{1}{x + 1})

What is the integral from-infinity to 0 of 1/(6-10x) ?
The integral from-infinity to 0 of 1/(6-10x) is diverges