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Popular >

derivative of 1y^2-7y^4(y+9y^3)

Solution

derivative of

1 y^{2} - 7 y^{4} (y + 9 y^{3})

Solution

2 y - 7 (63 y^{6} + 5 y^{4})

Solution steps

\frac{d}{d y} (1 \cdot y^{2} - 7 y^{4} (y + 9 y^{3}))

Simplify

1 \cdot y^{2} - 7 y^{4} (y + 9 y^{3}) : y^{2} - 7 y^{4} (y + 9 y^{3})

= \frac{d}{d y} (y^{2} - 7 y^{4} (y + 9 y^{3}))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d y} (y^{2}) - \frac{d}{d y} (7 y^{4} (y + 9 y^{3}))

\frac{d}{d y} (y^{2}) = 2 y

\frac{d}{d y} (7 y^{4} (y + 9 y^{3})) = 7 (63 y^{6} + 5 y^{4})

= 2 y - 7 (63 y^{6} + 5 y^{4})

Popular Examples

limit as x approaches 36 of (x^2)/9-4/x

x \to 36 lim (\frac{x ^{2}}{9} - \frac{4}{x})

integral of 7/(4+7x)

\int \frac{7}{4 + 7 x} d x

(\partial)/(\partial x)(3x^2y+xsin(2y))

\frac{\partial}{\partial x} (3 x^{2} y + x sin (2 y))

y^'=(3y^2-x^2)/(2xy)

y^{^{'}} = \frac{3 y ^{2} - x ^{2}}{2 x y}

y^'+sin(t)y=-sin(t),y(0)=7

y^{^{'}} + sin (t) y = - sin (t), y (0) = 7

Frequently Asked Questions (FAQ)

What is the derivative of 1y^2-7y^4(y+9y^3) ?
The derivative of 1y^2-7y^4(y+9y^3) is 2y-7(63y^6+5y^4)
What is the first derivative of 1y^2-7y^4(y+9y^3) ?
The first derivative of 1y^2-7y^4(y+9y^3) is 2y-7(63y^6+5y^4)