What is (d^2)/(dx^2)((x^2-3x)/(x+1)) ?

The answer to (d^2)/(dx^2)((x^2-3x)/(x+1)) is 8/((x+1)^3)

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(d^2)/(dx^2)((x^2-3x)/(x+1))

\frac{d ^{2}}{d x ^{2}} (\frac{x ^{2} - 3 x}{x + 1})

\frac{8}{( x + 1 ) ^{3}}

Solution steps

\frac{d ^{2}}{d x ^{2}} (\frac{x ^{2} - 3 x}{x + 1})

\frac{d}{d x} (\frac{x ^{2} - 3 x}{x + 1}) = \frac{x ^{2} + 2 x - 3}{( x + 1 ) ^{2}}

= \frac{d}{d x} (\frac{x ^{2} + 2 x - 3}{( x + 1 ) ^{2}})

\frac{d}{d x} (\frac{x ^{2} + 2 x - 3}{( x + 1 ) ^{2}}) = \frac{8}{( x + 1 ) ^{3}}

= \frac{8}{( x + 1 ) ^{3}}

n = 1 \sum \infty 6 e^{- 5 n}

\int \frac{12 x ^{3} - 24 x ^{2} + 5}{x ^{2} - 2 x} d x

\frac{\partial}{\partial x} (x + 4 y)

\int e^{2 x} 2 x d x

\frac{\partial}{\partial x} (x^{2} - y)

What is (d^2)/(dx^2)((x^2-3x)/(x+1)) ?
The answer to (d^2)/(dx^2)((x^2-3x)/(x+1)) is 8/((x+1)^3)