What is derivative of f(x)=sin(θ)cos(θ) ?

The answer to derivative of f(x)=sin(θ)cos(θ) is derivative of θ=0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of f(x)=sin(θ)cos(θ)

derivative of

f (x) = sin (θ) cos (θ)

\frac{d}{d x} (θ) = 0

Solution steps

f (x) = sin (θ) cos (θ)

Treat

θ

θ (x)

Differentiate both sides:

0 = cos^{2} (θ) \frac{d}{d x} (θ) - sin^{2} (θ) \frac{d}{d x} (θ)

Isolate

\frac{d}{d x} (θ) : \frac{d}{d x} (θ) = 0

\frac{d}{d x} (θ) = 0

\frac{d v}{d t} = - 2 v - 32

y^{^{''}} = - 16 y

x \to 1 lim (e^{8 x^{2} - 8 x})

f (x) = \frac{18 e ^{x}}{7 ^{x}}

f (x) = 2.4 x^{2} + 13 x

What is derivative of f(x)=sin(θ)cos(θ) ?
The answer to derivative of f(x)=sin(θ)cos(θ) is derivative of θ=0