What is the tangent of f(x)=x^5,\at x=4 ?

The tangent of f(x)=x^5,\at x=4 is y=1280x-4096

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tangent of f(x)=x^5,\at x=4

tangent of

f (x) = x^{5}, at x = 4

y = 1280 x - 4096

Solution steps

Find the tangent point:

(4, 1024)

Find the slope of

f (x) = x^{5} : \frac{df ( x )}{d x} = 5 x^{4}

Compute the slope of

f (x) = x^{5}

x = 4 : m = 1280

Find the line with slope m=

1280

and passing through

(4, 1024) : y = 1280 x - 4096

y = 1280 x - 4096

\int (x^{2} + 1) cos (2 x) d x

\int sin (2 x) e^{c o s (2 x)} d x

\int 7 x^{2} + 3 + \frac{6}{x ^{2} + 1} d x

\frac{d}{d x} (\frac{16}{( 5 - x ) ^{2}} - 1)

(\frac{π}{2})^{^{'}}

What is the tangent of f(x)=x^5,\at x=4 ?
The tangent of f(x)=x^5,\at x=4 is y=1280x-4096