What is the derivative of 3x^e+2e^x ?

The derivative of 3x^e+2e^x is 3ex^{e-1}+2e^x

What is the first derivative of 3x^e+2e^x ?

The first derivative of 3x^e+2e^x is 3ex^{e-1}+2e^x

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derivative of

3 x^{e} + 2 e^{x}

3 e x^{e - 1} + 2 e^{x}

Solution steps

\frac{d}{d x} (3 x^{e} + 2 e^{x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{e}) + \frac{d}{d x} (2 e^{x})

\frac{d}{d x} (3 x^{e}) = 3 e x^{e - 1}

\frac{d}{d x} (2 e^{x}) = 2 e^{x}

= 3 e x^{e - 1} + 2 e^{x}

\int \frac{x + 1}{x ( x - 2 ) ( x + 3 )} d x

6 x (x^{2} - 1)^{2}

\int x^{3} 0. 2^{- x} x d x

x \to + (- 2) lim (\frac{8}{x})

9 x ln (1 + 2 x)

What is the derivative of 3x^e+2e^x ?
The derivative of 3x^e+2e^x is 3ex^{e-1}+2e^x
What is the first derivative of 3x^e+2e^x ?
The first derivative of 3x^e+2e^x is 3ex^{e-1}+2e^x