What is the derivative of x^2+ax+b ?

The derivative of x^2+ax+b is 2x+a

What is the first derivative of x^2+ax+b ?

The first derivative of x^2+ax+b is 2x+a

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derivative of

x^{2} + a x + b

2 x + a

Solution steps

\frac{d}{d x} (x^{2} + a x + b)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d}{d x} (a x) + \frac{d b}{d x}

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (a x) = a

\frac{d b}{d x} = 0

= 2 x + a + 0

Simplify

= 2 x + a

\frac{\partial}{\partial x} (\frac{e ^{x}}{y + x ^{7}})

4 x^{3} - 18 x^{2} - 48 x

\frac{d}{d x} (4 - 2 x)

2 y = x, \frac{y ^{2}}{2} = x

\frac{d}{d x} (arcsec (x + 2))

What is the derivative of x^2+ax+b ?
The derivative of x^2+ax+b is 2x+a
What is the first derivative of x^2+ax+b ?
The first derivative of x^2+ax+b is 2x+a