What is (\partial)/(\partial x)(-4cos(3x)) ?

The answer to (\partial)/(\partial x)(-4cos(3x)) is 12sin(3x)

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(\partial)/(\partial x)(-4cos(3x))

\frac{\partial}{\partial x} (- 4 cos (3 x))

12 sin (3 x)

Solution steps

\frac{\partial}{\partial x} (- 4 cos (3 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 4 \frac{\partial}{\partial x} (cos (3 x))

Apply the chain rule:

- sin (3 x) \frac{\partial}{\partial x} (3 x)

= - sin (3 x) \frac{\partial}{\partial x} (3 x)

\frac{\partial}{\partial x} (3 x) = 3

= - 4 (- sin (3 x) \cdot 3)

Simplify

= 12 sin (3 x)

\int \frac{12 s + 12}{( s ^{2} + 1 ) ( s - 1 ) ^{3}} d s

\int \frac{1}{4 - x ^{2}} d x

\frac{d y}{d x} = (- \frac{3 y}{3 x + 2 y})

- 6 y^{^{''}} + 24 y = 0

\frac{\partial}{\partial y} (x y e^{x z})

What is (\partial)/(\partial x)(-4cos(3x)) ?
The answer to (\partial)/(\partial x)(-4cos(3x)) is 12sin(3x)