What is the limit as x approaches 0 of (ln(1+1/x))/x ?

The limit as x approaches 0 of (ln(1+1/x))/x is Does not exist

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limit as x approaches 0 of (ln(1+1/x))/x

x \to 0 lim (\frac{ln ( 1 + \frac{1}{x} )}{x})

Does not exist

Solution steps

x \to 0 lim (\frac{ln ( 1 + \frac{1}{x} )}{x})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 0 + lim (\frac{ln ( 1 + \frac{1}{x} )}{x}) = \infty

x \to 0 - lim (\frac{ln ( 1 + \frac{1}{x} )}{x}) =

Does not exist

= Does not exist

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\int (x^{2} + 2 x)^{5} (2 x + 2) d x

\frac{d}{d x} (x^{5} e^{- x})

\frac{d}{d x} (\frac{3 x + 5}{x ^{2} - x})

What is the limit as x approaches 0 of (ln(1+1/x))/x ?
The limit as x approaches 0 of (ln(1+1/x))/x is Does not exist