What is the derivative of (4x/(x+4)) ?

The derivative of (4x/(x+4)) is (16)/((x+4)^2)

What is the first derivative of (4x/(x+4)) ?

The first derivative of (4x/(x+4)) is (16)/((x+4)^2)

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\frac{d}{d x} (\frac{4 x}{x + 4})

\frac{16}{( x + 4 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{4 x}{x + 4})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 4 \frac{d}{d x} (\frac{x}{x + 4})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= 4 \cdot \frac{\frac{d x}{d x} ( x + 4 ) - \frac{d}{d x} ( x + 4 ) x}{( x + 4 ) ^{2}}

\frac{d x}{d x} = 1

\frac{d}{d x} (x + 4) = 1

= 4 \cdot \frac{1 \cdot ( x + 4 ) - 1 \cdot x}{( x + 4 ) ^{2}}

Simplify

4 \cdot \frac{1 \cdot ( x + 4 ) - 1 \cdot x}{( x + 4 ) ^{2}} : \frac{16}{( x + 4 ) ^{2}}

= \frac{16}{( x + 4 ) ^{2}}

y = 8 + 5 x^{2} - 2 x^{3}

\frac{4 s}{( s + 2 ) ^{2}}

\frac{d}{d y} (\frac{x}{y})

\int_{0}^{\frac{π}{12}} tan (6 x) d x

\frac{x + 6}{x ^{3} + x - 7}

What is the derivative of (4x/(x+4)) ?
The derivative of (4x/(x+4)) is (16)/((x+4)^2)
What is the first derivative of (4x/(x+4)) ?
The first derivative of (4x/(x+4)) is (16)/((x+4)^2)