What is the tangent of xy-picos(y)=3pi,(2,pi) ?

The tangent of xy-picos(y)=3pi,(2,pi) is y=-pi/2 x+2pi

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tangent of xy-picos(y)=3pi,(2,pi)

tangent of

x y - π cos (y) = 3 π, (2, π)

y = - \frac{π}{2} x + 2 π

Solution steps

Find the slope of

x y - π cos (y) = 3 π : \frac{d y}{d x} = - \frac{y}{x + π sin ( y )}

Compute the slope of

x y - π cos (y) = 3 π

(2, π) : m = - \frac{π}{2}

Find the line with slope m=

- \frac{π}{2}

and passing through

(2, π) : y = - \frac{π}{2} x + 2 π

y = - \frac{π}{2} x + 2 π

\frac{\partial}{\partial t} (\frac{2 r + s}{t})

\frac{d}{d x} (- 12 sin (6 x))

y = (3 x + 4)^{2}

x \to 0 lim (\frac{x ^{2} + 5}{3 ^{x}})

n = 1 \sum \infty (- 1)^{n} 2^{- n}

What is the tangent of xy-picos(y)=3pi,(2,pi) ?
The tangent of xy-picos(y)=3pi,(2,pi) is y=-pi/2 x+2pi