What is (\partial)/(\partial x)(sin(x^2)) ?

The answer to (\partial)/(\partial x)(sin(x^2)) is cos(x^2)*2x

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(\partial)/(\partial x)(sin(x^2))

\frac{\partial}{\partial x} (sin (x^{2}))

cos (x^{2}) \cdot 2 x

Solution steps

\frac{\partial}{\partial x} (sin (x^{2}))

Apply the chain rule:

cos (x^{2}) \frac{\partial}{\partial x} (x^{2})

= cos (x^{2}) \frac{\partial}{\partial x} (x^{2})

\frac{\partial}{\partial x} (x^{2}) = 2 x

= cos (x^{2}) \cdot 2 x

2 x - 5

\frac{d}{d x} (ln (\frac{1}{x x + 1}))

\frac{d}{d x} (arccos (\frac{1}{x}))

x \to 3 - lim (\frac{6 x}{x - 3})

\int sin (4 x - 7) d x

What is (\partial)/(\partial x)(sin(x^2)) ?
The answer to (\partial)/(\partial x)(sin(x^2)) is cos(x^2)*2x