What is (\partial)/(\partial x)((3x-2x^2)3) ?

The answer to (\partial)/(\partial x)((3x-2x^2)3) is 3(3-4x)

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(\partial)/(\partial x)((3x-2x^2)3)

\frac{\partial}{\partial x} ((3 x - 2 x^{2}) 3)

3 (3 - 4 x)

Solution steps

\frac{\partial}{\partial x} ((3 x - 2 x^{2}) \cdot 3)

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 \frac{\partial}{\partial x} (3 x - 2 x^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= 3 (\frac{\partial}{\partial x} (3 x) - \frac{\partial}{\partial x} (2 x^{2}))

\frac{\partial}{\partial x} (3 x) = 3

\frac{\partial}{\partial x} (2 x^{2}) = 4 x

= 3 (3 - 4 x)

\int (\frac{2 x}{x ^{2} + 1}) d x

\int 3 cos^{2} (x) tan^{3} (x) d x

x \to 0 - lim (4)

\frac{d}{d x} (ln (4 x^{6} + 2 x^{3}))

n = 0 \sum \infty n \cdot 2^{- n}

What is (\partial)/(\partial x)((3x-2x^2)3) ?
The answer to (\partial)/(\partial x)((3x-2x^2)3) is 3(3-4x)