What is the integral of cosh(9x) ?

The integral of cosh(9x) is 1/9 sinh(9x)+C

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integral of cosh(9x)

\int cosh (9 x) d x

\frac{1}{9} sinh (9 x) + C

Solution steps

\int cosh (9 x) d x

Apply u-substitution

: \int cosh (u) \frac{1}{9} d u

= \int cosh (u) \frac{1}{9} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{9} \cdot \int cosh (u) d u

Use the common integral:

\int cosh (u) d u = sinh (u)

= \frac{1}{9} sinh (u)

Substitute back

u = 9 x

= \frac{1}{9} sinh (9 x)

Add a constant to the solution

= \frac{1}{9} sinh (9 x) + C

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