What is (\partial)/(\partial x)(2-sqrt(x^2+y^2)) ?

The answer to (\partial)/(\partial x)(2-sqrt(x^2+y^2)) is -x/(sqrt(x^2+y^2))

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(\partial)/(\partial x)(2-sqrt(x^2+y^2))

\frac{\partial}{\partial x} (2 - x^{2} + y^{2})

- \frac{x}{x ^{2} + y ^{2}}

Solution steps

\frac{\partial}{\partial x} (2 - x^{2} + y^{2})

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (2) - \frac{\partial}{\partial x} (x^{2} + y^{2})

\frac{\partial}{\partial x} (2) = 0

\frac{\partial}{\partial x} (x^{2} + y^{2}) = \frac{x}{x ^{2} + y ^{2}}

= 0 - \frac{x}{x ^{2} + y ^{2}}

Simplify

= - \frac{x}{x ^{2} + y ^{2}}

\frac{1}{3 x}

y = sin (2 x), y = cos (2 x), x = 0, x = \frac{π}{4}

2 x^{2} - 10 x + 9

\frac{4 x ^{2} - 3}{x - 1}

\frac{2}{3 x + 5}

What is (\partial)/(\partial x)(2-sqrt(x^2+y^2)) ?
The answer to (\partial)/(\partial x)(2-sqrt(x^2+y^2)) is -x/(sqrt(x^2+y^2))